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Configuration = 90
cycles = (10 7 1 9 3)(8 5 2 6 4)

a = 1, b = 3, c = 7
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cycles = (10 7)(9 1)(8 3 6 4 2)(5)

a = 3, b = 6, c = 8
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cycles = (10 4)(9 1)(8 6 2)(7)(5)(3)

a = 4, b = 9, c = 10
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cycles = (10 1 4)(9 7 2)(8)(6)(5)(3)

a = 1, b = 4, c = 10
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cycles = (10)(9)(8 6 4)(7)(5)(3)(2)(1)